7n^2=35n

Solution for 7n^2=35n equation:

7n^2=35n

We move all terms to the left:

7n^2-(35n)=0

a = 7; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·7·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*7}=\frac{0}{14}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*7}=\frac{70}{14}
=5
$